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© Matthew Pinkney 2003

Binomial Theorem for Rational n

The Binomial Theorem for (1 + x)n

The previous version of the binomial theorem only works when n is a positive integer. If n is any fraction, the binomial theorem becomes:

(1 + x)n = 1 + nx + n(n - 1)x2 + n(n - 1)(n - 2)x3 + ...

1!

2!

3!

PROVIDING ½x½ < 1

Note that while the previous series stops, this one goes on forever.

 

Example

Find the expansion of (5x + 2)1/2

We need to transform this so it looks like (1 + x)1/2, so lets take out a factor of 2:

(5x + 2)1/2 = (2[5x/2 + 1])1/2

Now, where we have ‘x’ in the above formula, we need 5x/2 and where we have n, we need ½ .

= Ö2(1 + 5x/2)1/2
= Ö2[ 1 + ½ (5x/2) + ½ × ½ (- ½ )(25x2/4) + … ]

Remember, this is only valid if –1 < 5x/2 < 1, in other words, -2/5 < x < 2/5

Using Partial Fractions

We can expand more complicated expressions, now, using the method of partial fractions where appropriate.

Example

Expand 

        (6x + 3)      

 

(1 + x)(5x + 2)

We can split this up, using partial fractions, into:

  1      +     1            .
1 + x       5x + 2

Now expand (1 + x)-1 and (5x + 2)-1 as described above and add.