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Statistics Section |
ExpectationThe expected value (or mean) of X, where X is a discrete random variable, is a weighted average of the possible values that X can take, each value being weighted according to the probability of that event occurring. The expected value of X is usually written as E(X) or m.
So the expected value is the sum of: [(each of the possible outcomes) × (the probability of the outcome occurring)]. In more concrete terms, the expectation is what you would expect the outcome of an experiment to be on average. ExampleWhat is the expected value when we roll a fair die? There are six possible outcomes: 1, 2, 3, 4, 5, 6. Each of these has a probability of 1/6 of occurring. Let X represent the outcome of the experiment. Therefore P(X = 1) = 1/6 (this means that the probability
that the outcome of the experiment is 1 is 1/6) E(X) = 1×P(X = 1) + 2×P(X = 2) + 3×P(X = 3) + 4×P(X=4) + 5×P(X=5) + 6×P(X=6) Therefore E(X) = 1/6 + 2/6 + 3/6 + 4/6 + 5/6 + 6/6 = 7/2 So the expectation is 3.5 . If you think about it, 3.5 is halfway between the possible values the die can take and so this is what you should have expected. Expected Value of a Function of XTo find E[ f(X) ], where f(X) is a function of X, use the following formula:
ExampleFor the above experiment (with the die), calculate E(X2) Using our notation above, f(x) = x2 f(1) = 1, f(2) = 4, f(3) = 9, f(4) = 16, f(5) = 25, f(6) =
36 So E(X2) = 1/6 + 4/6 + 9/6 + 16/6 + 25/6 + 36/6 = 91/6 = 15.167 The expected value of a constant is just the constant, so for example E(1) = 1. Multiplying a random variable by a constant multiplies the expected value by that constant, so E[2X] = 2E[X]. A useful formula, where a and b are constants, is:
[This says that expectation is a linear operator]. VarianceThe variance of a random variable tells us something about the spread of the possible values of the variable. For a discrete random variable X, the variance of X is written as Var(X).
This can also be written as:
The standard deviation of X is the square root of Var(X). Note that the variance does not behave in the same way as expectation when we multiply and add constants to random variables. In fact:
You is because: Var[aX + b] = E[ (aX + b)2 ] - (E [aX + b])2 . = E[ a2X2 + 2abX + b2] - (aE(X)
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